0=35x^2+5x+150

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Solution for 0=35x^2+5x+150 equation: 



0=35x^2+5x+150

We move all terms to the left:

0-(35x^2+5x+150)=0

We add all the numbers together, and all the variables

-(35x^2+5x+150)=0

We get rid of parentheses

-35x^2-5x-150=0

a = -35; b = -5; c = -150;
Δ = b2-4ac
Δ = -52-4·(-35)·(-150)
Δ = -20975
Delta is less than zero, so there is no solution for the equation

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